4.3x^2+2x-10=23

Solution for 4.3x^2+2x-10=23 equation:

4.3x^2+2x-10=23

We move all terms to the left:

4.3x^2+2x-10-(23)=0

We add all the numbers together, and all the variables

4.3x^2+2x-33=0

a = 4.3; b = 2; c = -33;
Δ = b2-4ac
Δ = 22-4·4.3·(-33)
Δ = 571.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{571.6}}{2*4.3}=\frac{-2-\sqrt{571.6}}{8.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{571.6}}{2*4.3}=\frac{-2+\sqrt{571.6}}{8.6}
$